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0.1x^2-1.8=8.2
We move all terms to the left:
0.1x^2-1.8-(8.2)=0
We add all the numbers together, and all the variables
0.1x^2-10=0
a = 0.1; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·0.1·(-10)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*0.1}=\frac{-2}{0.2} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*0.1}=\frac{2}{0.2} =10 $
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